**Questions and Answers**

**2018 Mathematics Paper 2**

**1. Given that 2 log x ^{2}+log = k log x, find the value of k. (2 marks)**

2 log x^{2}+log√x=klogx

log(x^{4}x^{1/2}

=logx^{k}

k=1/2

**2. A variable P varies directly as t ^{3} and inversely as the square root of s. When t = 2 and s = 9, P = 16. Determine the equation connecting P, t and s, hence find P when s = 36 and t=3. (4 marks)**

**3. Asia invested some money in a financial institution. The financial institution offered 6% per annum compound interest in the first year and 7% per annum in the second year. At the end of the second year, Asia had Ksh 170 130 in the financial institution. Determine the amount of money Asia invested. (3 marks)**

p^{2}=170130

p^{2}=170130/1.07

=Ksh 150000

**4. The figure below represents a wedge ABCDEF. EF 10 cm, angle FBE 45° and the angle between the planes ABFE and ABCD is 20°.**

**Calculate length BC, correct to l decimal place.(3 marks)**

BF = 10 B1

Cos 20‘ BC/10

BC=10 Cos 20º

=9.4 cm

**5. Simplify √ 54 + ∛ 3/ √ 3 (2 marks)**

6. In the figure below, AB is a tangent to the circle, centre O and radius 6 cm. The arc AC subtends an angle of 60° at the centre of the circle.

Calculate the area of the shaded region, correct to 1 decimal place. (4 marks)

AB=6tan 60º or OB = 6/cos69

Area of triangle OAB =1/2x60x 6tan 60º

Area of sector OAC=60/360 x π x 6^{2}

Area of shaded part = 31.18 —18.85

— 12.3 cm^{2}

**7. Use completing the square method to solve 3x ^{2} + Sx — 6 = 0, correct to 3 significant figures.(3 marks)**

**8. Three workers, working 8 hours per day can complete a task in 5 days. Each worker is paic Ksh 40 per hour. Calculate the cost of hiring 5 workers if they work for 6 hours per day tc complete the same task. (3 marks)**

W : H : D

3 : 5 😡

No. of Days = 5x 8/6×3/5

=4days

cost=5x6x4x40

=Ksh4800

**9. The table below represents a relationship between two variables x and y.**

x | 1 | 2 | 3 | 4 | 5 | 6 |
---|---|---|---|---|---|---|

y | 3.5 | 4.5 | 8.0 | 8.5 | 11 | 13 |

**(a) On the grid provided draw the line of best fit.(3 marks)**

**(b) Use the graph to find the value off when x — 0.(1 marks)**

When = 0, y = 1

**10. State the amplitude and the phase angle of the curve y = 2sin x — 30° .(2 marks)**

Amplitude = 2

Phase angle = 30°

**11. The mass, in kilograms, of 9 sheep in a pen were: 13, 8, 16, 17, 19, 20, 15, 14 and 11.**

**Determine the quartile deviation of the data. (3 marks)**

**12. The position of two points C and D on the earth’s surface are (8°N, l 0OE) and (8°N, 30°E) respectively. The distance between the two points is 600 nm. Determine the latitude on which C and D lie. (3 marks)**

Longitude difference = 30 — 10 = 20°

600 — 20 x 60 Cos B

Cos 8 = 0.5

8 = 60°

Latitude = 60°N

**13. In the figure below OP — p, OR = r, PQ:QR = 1:2 and PS = 3PR.**

**Express QS in terms of p and r. (4 marks)**

**14. In a certain firm there are 6 men and 4 women employees. Two employees are chosen at random to attend a seminar. Determine the probability that a man and a woman are chosen. (3 marks)**

P(MW or WM) =6/10 + 4/9 + 4/10 + 6/9

24/90+24/90

=8/15

**15. Triangle OAB is mapped onto triangle OA’B’ with vertices O(0,0), A’(18,0) and B'(18, 6). Find the area of triangle OAB. (3 marks)**

**Section II**

**Answer any 5 questions from this section**

**17. The 5th and 10th terms of an arithmetic progression are 18 and —2 respectively. (a) Find the common difference and the first term. (4 marks)**

a + 4d= 18

a + 9d= — 2

5d = —20

a = 34

**(b) Determine the least number of terms which must be added together so that the sum of the progression is negative. Hence find the sum. (6 marks)**

**18.Complete the table below for the equation y=x ^{2}-4x+2**

(2 marks)

x | 0 | 1 | 2 | 3 | 4 | 5 |
---|---|---|---|---|---|---|

y |

**(b) On the grid provided draw the graph y = x ^{2} — 4x + 2 for 0≤ x ≤ 5. Use 2 cm to represent 1 unit on the x-axis and 1 cm to represent 1 unit on the y-axis. (3 marks)**

**(c) Use the graph to solve the equation, x ^{2} — 4x + 2 = 0 (2 marks)**

x=0.6± 0.05

x=3.4 ± 0.05

**(d) By drawing a suitable line, use the graph in (b) to solve the equation A-2 — 5x + 3 = O. (3 marks)**

**(c) Determine the probability that a plant taken at random has a height greater than 40 cm. (2 marks)**

No. of plants whose height>40 = 4+2=6

p(height>40cm)=6/40=0.15

**20. (a) Using a ruler and a pair of compasses only, construct:**

**(i) a parallelogram ABCD, with line AB below as part of it, such that AD = 7 cm and angle BAD = 600; (3 marks)**

**(ii) the locus of points equidistant from AB and AD; (1 mark)**

Angle bisector of **(iii) the perpendicular bisector of BC. (1 mark)**

bisector of BC ✓ drawn

**(b) (i) Mark the point P that lies on DC and is equidistant from AB and AD. (1 mark)**

Point P identified and ✓ marked on line DC

**(ii) Measure BP. (1 mark)**

BP = 7 ± O. 1 cm

**(c) Describe the locus that the perpendicular bisector of BC represents. (1 mark)**

Locus of Points equidistant from B and C

(d) Calculate the area of trapezium ABCP. (2 marks)

**21. The table below shows some values of the curves y = 2 cos x and y = 3 sin x.**

**(a) Complete the table for values of y = 2 cos x and y = 3 sin x, correct to 1 decimal place. (2 marks)**

**(c) Use the graph to find the values of x when 2 cos x — 3 sin x = 0 (2 marks)**

2cosx-3sinx=0

=2cosx=3sinx

x=34° and x=214°

**(d) Use the graph to find the values of y when 2 cos x = 3 sin x. (1 marks)**

y=1.6 and y = -1.6

**22. The figure below is a model of a watch tower with a square base of side 10 cm. Height PU is 15 cm and slanting edges UV = TV = SV = RV = 13 cm.**

**Giving the answer correct to two decimal places, calculate:**

**(a) length MP; (2 marks)**

MP^{2}=10^{2}+10^{2}

MP=√ 200 =14.14

**(b) the angle between MU and plane MNPQ; (2 marks)**

**(d) The angle between planes VST and RSTU; (3 marks)**

**In that year a monthly personal tax relief of Ksh 1 280 was allowed. In a certain month of that year, Sila earned a monthly basic salary of Ksh 52 000, a house allowance of Ksh 7 800 and a commuter allowance of Ksh 5 000.**

**(a) Calculate:**

Taxable income = 52000 + 7800 + 5000 = Ksh 64800

**(i) Sila’s taxable income;(3 marks)**

Tax payable 11180×0.1=1118

10534x 0.15 =1580.10

10534 x0.2 = 2106.80

10534x 0.25 = 2633.50

22018x 0.3 = 6605.4

Total tax = 14043.8

**(ii) the net tax payable by Sila in that month;(5 marks)**

Net tax = 14043.8 —1280 = 12763.8

**(b) In July that year, Sila’s basic salary was raised by 4%. Determine Sila’s net salary in July.(3 marks)**

Additional tax = 4/100 x 52000 x 0.3 100 = Ksh 624

40 Net salary = 64800 — 12763.8 — 624 + (4/100 x 52 000)

= Ksh 53492.20

**24 A hotel buys beef and mutton daily. The amount of beef bought must be at least 30kg and that of mutton at least 20 kg. The total mass of beef and mutton bought should not exceed 100 kg. The beef is bought at Ksh 360 per kg and the mutton at Ksh 480 per kg.**

**The amount of money spent on both beef and mutton should not exceed Ksh 43 200 per day. Let x represent the number of kilograms of beef and y the number of kilograms of mutton.**

**(a) Write the inequalities that represent the above information.(3 marks)**

x≥30; y≥20

x+y=≤100

360x+480≤43200 0r 3x+4y≤360

**(b) On the grid provided, draw the inequalities in (a) above.(3 marks)**

**(c) The hotel makes a profit of ksh 50 on each kg of beef and ksh 60 on each kg of mutton. Determine the maximum profit the hotel can make (3 marks)**

objective function = 50x+60y

profit=50×60+60×60

=5600